Describe doping and the difference between n-type and p-type silicon.
Explain how the depletion region and built-in potential form.
Describe forward and reverse bias qualitatively.
State why a diode conducts in only one direction.
Circuit Analysis was built entirely from elements that treat both directions alike: a resistor does not care which way current flows, and neither does a capacitor or an inductor. Every element you have met is symmetric and linear. Microelectronics begins by breaking both properties at once, with a device made of two kinds of doped silicon pressed together. The result conducts one way and blocks the other — and that asymmetry is the seed of rectifiers, logic, memory, and every transistor in the machine you are reading this on.
Pure silicon is a poor conductor: each atom's four valence electrons are locked into covalent bonds. Doping deliberately contaminates it. Add a pentavalent atom such as phosphorus and its fifth electron is left over, free to roam: the result is n-type silicon, where the mobile charge carriers are electrons. Add a trivalent atom such as boron and a bond is left short one electron — a hole — which neighbouring electrons hop into, so the vacancy itself migrates like a positive particle: p-type silicon, where the carriers are holes. Both materials are electrically neutral overall; doping changes what can MOVE, not the net charge.
Now join them. Free electrons near the boundary diffuse into the p-side and fall into holes; holes diffuse the other way. Each crossing leaves behind a fixed, charged dopant ion — negative on the p-side, positive on the n-side — and this exposed layer of immobile charge is the depletion region, so called because the mobile carriers there have been consumed. The charge it holds creates an electric field pointing from the n-side to the p-side, which opposes further diffusion. Equilibrium arrives when the field's opposition exactly balances the diffusion tendency, leaving a built-in potential across the junction: roughly 0.7 V for silicon, about 0.3 V for germanium.
A PN junction at equilibrium: the depletion region holds only fixed ions, whose field opposes further diffusion.WORKED EXAMPLE
Why the asymmetry is structural
A resistor's conduction comes from carriers that are present everywhere in it, always — so reversing the voltage just reverses the current.
A junction's conduction requires carriers to CROSS a barrier region that has none of its own.
Forward bias shrinks that barrier; reverse bias grows it. The device's geometry changes with the applied voltage, which is precisely what a linear element never does.
The diode is nonlinear because its internal structure responds to the bias.WORKED EXAMPLE
Reading a diode symbol
The triangle points from anode (p-side) toward cathode (n-side); the bar is the cathode.
The symbol is an arrow in the direction of easy conventional current: anode to cathode.
On a real part the cathode is marked with a painted band — matching the bar. Getting it backwards is the single most common assembly error on a first board.
Triangle-then-bar = the direction current is allowed to flow.
PRACTICE
Q1
A silicon sample is doped with boron. Is it n-type or p-type, and what are its majority carriers?
Q2
In two sentences, explain why the depletion region contains almost no mobile carriers.
Q3
A diode has its anode at +5 V and its cathode at +4.5 V. Is it forward or reverse biased, and roughly what current do you expect from a silicon diode?
Q4
Why does reverse bias produce a small but nonzero leakage current, and what happens to it as temperature rises?